document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=363339>Question 363339</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 30 inches, and its area is 36 in2. Find its length and width.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #259049 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=259049\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2l +2w = 30, or l+w = 15.  we have l = 15 - w.<BR>\n" );
document.write( "Also, area is lw = 36.  By direct substitution, (15 - w)w = 36.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=15w+-+w%5E2+=+36 ALIGN=MIDDLE  ALT=\"15w+-+w%5E2+=+36\"   DISABLED_style= \"max-width:90%; height:auto;\" >,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=w%5E2+-+15w%2B36+=+0 ALIGN=MIDDLE  ALT=\"w%5E2+-+15w%2B36+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" >,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28w-3%29%28w-12%29+=+0 ALIGN=MIDDLE  ALT=\"%28w-3%29%28w-12%29+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" >,<BR>\n" );
document.write( "w = 3 or w = 12.  The rectangle is 3\"x 12\". </SPAN>\n" );
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