document.write( "Question 363241: The 12-foot bed of a dump truck loaded with heavy stone must rise to an angle of 36° before the stone will spill out. Approximately how high must the front of the bed rise (x) to unload?
\n" ); document.write( "sin 36° ≈ 0.588, cos 36° ≈ 0.810, tan 36° ≈ 0.727\r
\n" ); document.write( "\n" ); document.write( "I have no clue how to work with Sine and Cosine.\r
\n" ); document.write( "\n" ); document.write( "How do I work this out?\r
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The 12-foot bed of a dump truck loaded with heavy stone must rise to an angle of 36° before the stone will spill out. Approximately how high must the front of the bed rise (x) to unload?
\n" ); document.write( "sin 36° ≈ 0.588.\r
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\n" ); document.write( "\n" ); document.write( "Let a° represent the angle made by the bed of the truck when it is raised.
\n" ); document.write( "By definition (adjacent side) times sin a° = opposite side
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\n" ); document.write( "\n" ); document.write( "(12 feet) times sin 36°= x feet
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\n" ); document.write( " x = 12 sin 36°
\n" ); document.write( " x = 12(0.588)
\n" ); document.write( " x = 7.056 feet\r
\n" ); document.write( "\n" ); document.write( "mathteacher2010@aol.com
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