document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=363205>Question 363205</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At 9:00 am, your friends begin hiking at 2 miles per hour. You begin from the same place at 9:25 am. You hike at 3 miles per hour. How long will you have hiked when you catch up with your friends? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #258988 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=258988\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "D=2T FOR THE FIRST HIKER.<BR>\n" );
document.write( "D=3(T-25/60) FOR THE SECOND HIKER.<BR>\n" );
document.write( "2T=3(T-.41667)<BR>\n" );
document.write( "2T=(3T-1.25)<BR>\n" );
document.write( "2T-3T=-1.25<BR>\n" );
document.write( "-T=-1.25<BR>\n" );
document.write( "T=1.25 HOURS OR 1:15 MINUTES AFTER THE SECOND HIKER LEAVES HE WILL MEET THE FIRST HIKER.<BR>\n" );
document.write( "9:25+1:15=10:40 IS WHEN THEY WILL MEET.<BR>\n" );
document.write( "2*1.25=3(1.25-.41667)<BR>\n" );
document.write( "2.5=3(.8333)<BR>\n" );
document.write( "2.5=2.5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );