document.write( "Question 363211: A chemist wants to make 50 mL of a 17% acid solution by mixing a 13% acid solution and an 18% acid solution. How many milliliters of each solution should the chemist use? \n" ); document.write( "
Algebra.Com's Answer #258975 by Fombitz(32388)\"\" \"About 
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Let A be the amount of 13% solution, B the amount of 18% solution.
\n" ); document.write( "1.\"A%2BB=50\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "\"13A%2B18B=17%2850%29\"
\n" ); document.write( "2.\"13A%2B18B=850\"
\n" ); document.write( "Multiply eq. 1 by (-13) and add to eq. 2,
\n" ); document.write( "\"-13A-13B%2B13A%2B18B=-650%2B850\"
\n" ); document.write( "\"5B=200\"
\n" ); document.write( "\"highlight%28B=40%29\"ml
\n" ); document.write( "Then from eq. 1,
\n" ); document.write( "\"A%2B40=50\"
\n" ); document.write( "\"highlight%28A=10%29\"ml
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