document.write( "Question 363197: Hello, I appeciate very much that there are people like you up there; willin and dedicated to help people like me. Thank you very much for your effort.
\n" ); document.write( "My dilemma is and have always been word problems. They are not like other math problems where you just follow or apply a given formula. Words problems are always changin and I never know when to use what. I've always had difficulty translating words to the actual equation which by the way I have no problem solving. If there is some guidelines you can show me as to when I use what, I would appreciate it very, very much. The problems are:\r
\n" ); document.write( "\n" ); document.write( "1) Henry has $1.35 in nickels and dimes. There are 9 more nickels than dimes. find the number he has of each kind.\r
\n" ); document.write( "\n" ); document.write( "2) Mark has $5.05 in quarters and dimes. The number of quarters exceeds twice the number of dimes by 1. Find the number he has of each.\r
\n" ); document.write( "\n" ); document.write( "raulmiller@optonline.net
\n" ); document.write( "

Algebra.Com's Answer #258946 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Hi,
\n" ); document.write( "Note***convert these problems to how many pennys or cents (they are all done that way)
\n" ); document.write( "1)Let x represent the number of dimes, then (x+9)is the number of nickels
\n" ); document.write( "5(x+9) + 10x = 135cents
\n" ); document.write( "solve for x \r
\n" ); document.write( "\n" ); document.write( "2) Let x represent the number of dimes, then (2x+1)is the number of quarters
\n" ); document.write( "10x + 25(2x+1) = 505 cents
\n" ); document.write( "solve for x
\n" ); document.write( "60x + 25 = 505
\n" ); document.write( "60x = 480
\n" ); document.write( "x = 8 dimes and therefore (2*8+1) quarters Or 17 quarters
\n" ); document.write( "checking our answer
\n" ); document.write( "80 + 425 = 505cents Or $5.05 \n" ); document.write( "
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