document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=363157>Question 363157</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me factor this polynomial: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8x%5E3-12x%5E2%2B6x-1 ALIGN=MIDDLE  ALT=\"8x%5E3-12x%5E2%2B6x-1\"   DISABLED_style= \"max-width:90%; height:auto;\" >. I am trying to figure out how to solve it using the factor theorem. My answer key uses 2 as the factor of the constant term. And then the synthetic division looks like this:                               1-6 12-8<BR>\n" );
document.write( "                                                        2- 8 8<BR>\n" );
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document.write( "I do not understand how you can use 2 as the factor of the constant term. Thank you for your assistance. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #258920 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=258920\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Please help me factor this polynomial:8x^3-12x^2+6x-1 . I am trying to figure out how to solve it using the factor theorem. My answer key uses 2 as the factor of the constant term. <BR>\n" );
document.write( "And then the synthetic division looks like this: 1-6 12-8<BR>\n" );
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document.write( "I graphed the cubic and found a zero at x = 1/2.<BR>\n" );
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document.write( "(1/2)....8....-12....6....-1<BR>\n" );
document.write( "..........8......-8....2...| 0\r<BR>\n" );
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document.write( "Factors: (2x-1)(8x^2 - 8x + 2)<BR>\n" );
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document.write( "You can factor further.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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