document.write( "Question 40499: Could someone please help explain to me how to figue this problem?\r
\n" ); document.write( "\n" ); document.write( "h(x) = -3x^2
\n" ); document.write( " I need to state the domain and range of this quadratic function as well as its solution set in interval notation. Any ideas?
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Algebra.Com's Answer #25892 by Nate(3500)\"\" \"About 
You can put this solution on YOUR website!
The vertex is at the origin. Since \"a\" is negative, the parabola opens down. The domain: all real values .... The range: \"y%3C=0\".
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"-3x%5E2%2B0x%2B0+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%280%29%5E2-4%2A-3%2A0=0\".
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\n" ); document.write( " Discriminant d=0 is zero! That means that there is only one solution: \"x+=+%28-%280%29%29%2F2%5C-3\".
\n" ); document.write( " Expression can be factored: \"-3x%5E2%2B0x%2B0+=+-3%28x-0%29%2A%28x-0%29\"
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\n" ); document.write( " Again, the answer is: 0, 0.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+-3%2Ax%5E2%2B0%2Ax%2B0+%29\"
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