document.write( "Question 363157: Please help me factor this polynomial: $\"8x%5E3-12x%5E2%2B6x-1\"$ . I am trying to figure out how to solve it using the factor theorem. My answer key uses 2 as the factor of the constant term. And then the synthetic division looks like this: 1-6 12-8
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\n" ); document.write( "I do not understand how you can use 2 as the factor of the constant term. Thank you for your assistance. \n" ); document.write( "

Algebra.Com's Answer #258914 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "Hi, \r\n" );
document.write( "substituion verifies that 1/2 is a root (1 - 3 + 3 - 1 = 0)\r\n" );
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document.write( "          8x^2 -   8x +     2\r\n" );
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document.write( "(x -.5) | 8x^3 -  12x^2 +   6x - 1\r\n" );
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document.write( "applying quadratic equation
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document.write( "x = 1/2
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document.write( "factoring  would result as: 
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document.write( "(x-.5)(x -.5)(x -.5) \n" );
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