document.write( "Question 40495: The length of a rectangle is 2cm more than twice its width. If the perimeter of the rectangle is 52cm, find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #25891 by Nate(3500)![]() ![]() ![]() You can put this solution on YOUR website! Length = 2w + 2 \n" ); document.write( "Width = w \n" ); document.write( "Equation: \n" ); document.write( "2w + 2l = 52 \n" ); document.write( "2w + 2(2w + 2) = 52 \n" ); document.write( "2w + 4w + 4 = 52 \n" ); document.write( "6w = 48 \n" ); document.write( "w = 8 \n" ); document.write( "The width is eight units, and the length is 18 units. \n" ); document.write( " |