document.write( "Question 362684: Solve, Show your work to help me understand.\r
\n" ); document.write( "\n" ); document.write( "The length of a rectangle is 3 times the width. if the length is increased by 4cm and the width is decreased by 1cm, the perimeter will be 102cm. Find the dimensions of the origional rectangle.
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Algebra.Com's Answer #258870 by ankor@dixie-net.com(22740)\"\" \"About 
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The length of a rectangle is 3 times the width.
\n" ); document.write( " if the length is increased by 4cm and the width is decreased by 1cm,
\n" ); document.write( " the perimeter will be 102cm.
\n" ); document.write( "Find the dimensions of the original rectangle.
\n" ); document.write( ":
\n" ); document.write( "Let x = the width of the original rectangle
\n" ); document.write( "It says, \"length of a rectangle is 3 times the width.\"; so we have;
\n" ); document.write( "3x = the length of the original rectangle
\n" ); document.write( "then
\n" ); document.write( "(3x + 4) = length of the new rectangle
\n" ); document.write( "and
\n" ); document.write( "(x-1) = width of the new rectangle
\n" ); document.write( ":
\n" ); document.write( "Perimeter of the new rectangle:
\n" ); document.write( "2(3x+4) + 2(x-1) = 102
\n" ); document.write( "Simplify, divide by 2 and we have:
\n" ); document.write( "3x + 4 + x - 1 = 51
\n" ); document.write( "4x + 3 = 51
\n" ); document.write( "4x = 51 - 3
\n" ); document.write( "4x = 48
\n" ); document.write( "x = \"48%2F4\"
\n" ); document.write( "x = 12 cm is the original width
\n" ); document.write( "then
\n" ); document.write( "3(12) = 36 cm is the original length
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check the perimeter with these values
\n" ); document.write( "2(36+4) + 2(12-1) =
\n" ); document.write( "2(40) + 2(11) = 102, confirms our solutions
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