document.write( "Question 363069: A lab has a 20% acid solution and a 50% acid solution. How many liters of each are required to obtain 600 liters of a30% solution? \n" ); document.write( "

Algebra.Com's Answer #258820 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi, 
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document.write( "Let x represent the amount of the 50% solution, (600 - x) would then represent the 20% solution
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document.write( ".20(600L - x) + .50x = .30*600L
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document.write( ".20*600L - .20x + .50x = .30*600L
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document.write( ".30x = .10*600L
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document.write( "x = 200L of 50% solution and 400L of 20% solution are needed\r
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document.write( "checking our answer
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document.write( ".20*400L + .50*200L = 80L + 100L = 180L = .30*600L \n" );
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