document.write( "Question 362889: Due to melting, an ice sculpture loses one-half its weight every hour. After 8 hours, it weighs 5/16 of a pound. How much did it weigh in the beginning.\r
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document.write( "I did 5/16+8 and put the fraction into decimal form then added the two together and got 8.3125. Then its says 1/2 of the that is lost in weight. Now I multiplied the 8.3125 to .05(The decimal of 1/2) then got 4.15625. I dont know if that is correct or what and i used samdep instead of pemdas its pemdas backwards because it says to solve backwards using asmdep. \n" );
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Algebra.Com's Answer #258813 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! Let's say it weighed \n" ); document.write( "After \n" ); document.write( "After \n" ); document.write( "After \n" ); document.write( "After \n" ); document.write( "After \n" ); document.write( "After \n" ); document.write( "After \n" ); document.write( "After \n" ); document.write( "But you know that \n" ); document.write( " \n" ); document.write( "So then, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "You could also work it backwards, \n" ); document.write( "After \n" ); document.write( "After \n" ); document.write( "After \n" ); document.write( "After \n" ); document.write( "After \n" ); document.write( "After \n" ); document.write( "After \n" ); document.write( "After \n" ); document.write( "After \n" ); document.write( " \n" ); document.write( " |