document.write( "Question 363042: A salesman sells a car to one out of 20 customers. What is the probability that he will sell two out of three cars? \n" ); document.write( "
Algebra.Com's Answer #258770 by Theo(13342)\"\" \"About 
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the probability that he will sell 1 car is (1/20) = .05\r
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\n" ); document.write( "\n" ); document.write( "the probability that he will sell exactly 2 out of 3 cars is equal to:\r
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\n" ); document.write( "\n" ); document.write( ".05 * .05 * .95 * the number of ways this can happen.\r
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\n" ); document.write( "\n" ); document.write( "the number of ways this can happen is 3! / (2! * 1!) = 3\r
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\n" ); document.write( "\n" ); document.write( "the general equation for that is n! / (x! * (n-x)!)\r
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\n" ); document.write( "\n" ); document.write( "n is the total members of the set.
\n" ); document.write( "x is the number of members of the set that you draw from.\r
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\n" ); document.write( "\n" ); document.write( "n is equal to 3 which is the total number of cars that can be sold.
\n" ); document.write( "x is equal to 2 which is the number of cars from the total number of cars that this salesmen will sell.\r
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\n" ); document.write( "\n" ); document.write( "the probability is therefore equal to .05 * .05 * .95 * 3 = .007125\r
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\n" ); document.write( "\n" ); document.write( "the 3 possible ways are:\r
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\n" ); document.write( "\n" ); document.write( "he sells the 1st and 2d car but not the 3d.
\n" ); document.write( "he sells the 1st and 3d car but not the 2d.
\n" ); document.write( "he sells the 2d and 3d car but not the 1st.\r
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\n" ); document.write( "\n" ); document.write( "since there are 3 possible ways and the probability for each way is the same, then the total probability is 3 * the probability for each way.\r
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\n" ); document.write( "\n" ); document.write( "the probability for each way is .05 * .05 * .95 (first way) which is the same as .05 * .95 * .05 (second way) which is the same as .95 * .05 * .05 (third way).\r
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