document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=362899>Question 362899</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is three feet more than twice the width . the area of the rectangle is 9 square feet. find the length and the width. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #258753 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=258753\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> width =x<BR>\n" );
document.write( "length = 2x+3<BR>\n" );
document.write( "area =9<BR>\n" );
document.write( "...<BR>\n" );
document.write( "x(2x+3)=9<BR>\n" );
document.write( "2x^2+3x=9<BR>\n" );
document.write( "2x^2+3x-9=0<BR>\n" );
document.write( "2x^2+6x-3x-9=0<BR>\n" );
document.write( "2x(x+3)-3(x+3)=0<BR>\n" );
document.write( "(x+3)(2x-3)=0<BR>\n" );
document.write( "x= 3/2 feet the width<BR>\n" );
document.write( ".<BR>\n" );
document.write( "length = 2x+3 = 6 feet<BR>\n" );
document.write( "..<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );