document.write( "Question 363018: 40 coins , nickel, dimes and quarters worth $4.05. 7 more nickels than dimes. How many quarters ? \n" ); document.write( "
Algebra.Com's Answer #258742 by mananth(16946)\"\" \"About 
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dimes=x
\n" ); document.write( "nickels=x+7
\n" ); document.write( "..
\n" ); document.write( "nickels + dimes = 2x+7
\n" ); document.write( "quarters = 40-(2x+7)
\n" ); document.write( "..
\n" ); document.write( "405 cents
\n" ); document.write( "10x+5(x+7)+25(40-2x-7)=405
\n" ); document.write( "10x+5x+35+825-50x=405
\n" ); document.write( "-35x=-825-35+405
\n" ); document.write( "-35x=-455
\n" ); document.write( "x= 13 dimes
\n" ); document.write( "nickels = x+7 = 20
\n" ); document.write( "quarters = 7
\n" ); document.write( "..
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( "7*25+20*5+10*13=405\r
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