document.write( "Question 363007: A company manufactures both mountain bikes and trail bikes.The cost of materials for a mountain bike is $70, and the cost of materials for a trail bike is $50. The cost of labor to manufacture a trail bike is $80, and the cost of labor to manufacture a trail bike is $40. During a week in which the company has budgeted $2500 for materials and $2600 for labor, how many mountain bikes does the company plan to manufacture? \n" ); document.write( "
Algebra.Com's Answer #258738 by mananth(16946)\"\" \"About 
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materials for a mountain bike is $70,
\n" ); document.write( "cost of materials for a trail bike is $50.
\n" ); document.write( "cost of labor to manufacture a mountain bike is $80,
\n" ); document.write( "cost of labor to manufacture a trail bike is $40.
\n" ); document.write( "..
\n" ); document.write( "budgeted $2500 for materials
\n" ); document.write( "$2600 for labor,
\n" ); document.write( "...
\n" ); document.write( "let x be mountain bikes
\n" ); document.write( "y be trail bikes
\n" ); document.write( "..
\n" ); document.write( "70x+50y=2500.......................1
\n" ); document.write( "80x+40y=2600.......................2
\n" ); document.write( "...
\n" ); document.write( "multiply equation 1 by -8 & equation 2 by 7
\n" ); document.write( "-560x-400y=-20000
\n" ); document.write( "560x+280y=18200
\n" ); document.write( "add the two
\n" ); document.write( "-120y= -1800
\n" ); document.write( "/-120
\n" ); document.write( "y=1800/-120
\n" ); document.write( "y =15 trail bikes
\n" ); document.write( "plug the value of y
\n" ); document.write( "70x+50*15=2500
\n" ); document.write( "70x=2500-750
\n" ); document.write( "70x=1750
\n" ); document.write( "x= 25 mountain bikes
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( "
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