document.write( "Question 363007: A company manufactures both mountain bikes and trail bikes.The cost of materials for a mountain bike is $70, and the cost of materials for a trail bike is $50. The cost of labor to manufacture a trail bike is $80, and the cost of labor to manufacture a trail bike is $40. During a week in which the company has budgeted $2500 for materials and $2600 for labor, how many mountain bikes does the company plan to manufacture? \n" ); document.write( "
Algebra.Com's Answer #258738 by mananth(16946)![]() ![]() You can put this solution on YOUR website! materials for a mountain bike is $70, \n" ); document.write( "cost of materials for a trail bike is $50. \n" ); document.write( "cost of labor to manufacture a mountain bike is $80, \n" ); document.write( "cost of labor to manufacture a trail bike is $40. \n" ); document.write( ".. \n" ); document.write( "budgeted $2500 for materials \n" ); document.write( "$2600 for labor, \n" ); document.write( "... \n" ); document.write( "let x be mountain bikes \n" ); document.write( "y be trail bikes \n" ); document.write( ".. \n" ); document.write( "70x+50y=2500.......................1 \n" ); document.write( "80x+40y=2600.......................2 \n" ); document.write( "... \n" ); document.write( "multiply equation 1 by -8 & equation 2 by 7 \n" ); document.write( "-560x-400y=-20000 \n" ); document.write( "560x+280y=18200 \n" ); document.write( "add the two \n" ); document.write( "-120y= -1800 \n" ); document.write( "/-120 \n" ); document.write( "y=1800/-120 \n" ); document.write( "y =15 trail bikes \n" ); document.write( "plug the value of y \n" ); document.write( "70x+50*15=2500 \n" ); document.write( "70x=2500-750 \n" ); document.write( "70x=1750 \n" ); document.write( "x= 25 mountain bikes \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |