document.write( "Question 362991: could you show me how to set this problem up. A collection of nickels, dimes and quarters totals $3.40. the total number of coins is 32, and there are twice as many dimes as quarters. how many of each are there.
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Algebra.Com's Answer #258724 by mananth(16949) You can put this solution on YOUR website! quarters------------dimes----------nickels \n" ); document.write( "x------------------2x--------------32-3x \n" ); document.write( "value = 340 cents total 32 coins ::: dimes & quarters = 3x \n" ); document.write( "... \n" ); document.write( "25x+10*2x+5(32-3x)=340 \n" ); document.write( "25x+20x+160-15x=340 \n" ); document.write( "30x=340-160 \n" ); document.write( "30x=180 \n" ); document.write( "/30 \n" ); document.write( "x=6 quarters \n" ); document.write( "... \n" ); document.write( "dimes = 2x= 12 \n" ); document.write( "nickels = 32-3x= 14 \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( "... \n" ); document.write( " \n" ); document.write( " |