document.write( "Question 362991: could you show me how to set this problem up. A collection of nickels, dimes and quarters totals $3.40. the total number of coins is 32, and there are twice as many dimes as quarters. how many of each are there.
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Algebra.Com's Answer #258724 by mananth(16949)\"\" \"About 
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quarters------------dimes----------nickels
\n" ); document.write( "x------------------2x--------------32-3x
\n" ); document.write( "value = 340 cents total 32 coins ::: dimes & quarters = 3x
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\n" ); document.write( "25x+10*2x+5(32-3x)=340
\n" ); document.write( "25x+20x+160-15x=340
\n" ); document.write( "30x=340-160
\n" ); document.write( "30x=180
\n" ); document.write( "/30
\n" ); document.write( "x=6 quarters
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\n" ); document.write( "dimes = 2x= 12
\n" ); document.write( "nickels = 32-3x= 14
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\n" ); document.write( "m.ananth@hotmail.ca
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