document.write( "Question 39647This question is from textbook Beginning Algebra
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document.write( ": (x/3 + 3/4)(3x/4 -3/5) \n" );
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Algebra.Com's Answer #25867 by tran3209(100)![]() ![]() ![]() You can put this solution on YOUR website! (x/3+3/4)(3x/4-3/5)\r \n" ); document.write( "\n" ); document.write( "(4x+9/12)(15x-12/20)\r \n" ); document.write( "\n" ); document.write( "(4x+9)(15x-12)/(12)(20)\r \n" ); document.write( "\n" ); document.write( "60X^2-48x+135x-108/(12)(20)\r \n" ); document.write( "\n" ); document.write( "60X^2+87x-108/(12)(20)\r \n" ); document.write( "\n" ); document.write( "put 3 in factor in the numerator.\r \n" ); document.write( "\n" ); document.write( "3(20x^2+29x-36)/(12)(20) simplify the numerator and the denominator by 3\r \n" ); document.write( "\n" ); document.write( "20x^2+29x-36/80\r \n" ); document.write( "\n" ); document.write( "The answer is : 20x^2+29x-36/80 \n" ); document.write( " |