document.write( "Question 362881: find three consecutive positive numbers such that the product of the first and third, minus the second,is 1 more than 3 times the third\r
\n" ); document.write( "\n" ); document.write( "the smallest integer is __ , the second smallest integer is ___, the largest integer is ___\r
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Algebra.Com's Answer #258663 by HasanSahin(52)\"\" \"About 
You can put this solution on YOUR website!
one of the classics..observe..
\n" ); document.write( "Let's say x,x+1,x+2 for the consecutive integers..\r
\n" ); document.write( "\n" ); document.write( "x*(x+2)-(x+1) = 3*(x+2)+1\r
\n" ); document.write( "\n" ); document.write( "x^2+2x-x-1 = 3x+6+1\r
\n" ); document.write( "\n" ); document.write( "x^2-2x-8 = 0\r
\n" ); document.write( "\n" ); document.write( "(x-4)*(x+2) = 0\r
\n" ); document.write( "\n" ); document.write( "x={4,-2}\r
\n" ); document.write( "\n" ); document.write( "You must choose as x = 4 because the integers are positive..
\n" ); document.write( "So that,4,5,6 are the integers..\r
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