document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=40466>Question 40466</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A roler has some $4/lb coffee and some $8/lb coffee that she will mix to make 50 lb of $5.60/lb coffee. How many pounds of each should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #25866 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=25866\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A roler has some $4/lb coffee and some $8/lb coffee that she will mix to make 50 lb of $5.60/lb coffee. How many pounds of each should be used?\r<BR>\n" );
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document.write( "Let amount of $4 coffee be \"x\" lbs.<BR>\n" );
document.write( "Then amount of $8 coffee is \"50-x\" lbs.<BR>\n" );
document.write( "Value of this $4 coffee is 4x dollars.<BR>\n" );
document.write( "Value of the $8 coffee is 8(50-x)=400-8x dollars<BR>\n" );
document.write( "Value of the mix is 5.6(50)= 280 dollars<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "value + value = value<BR>\n" );
document.write( "4x+400-8x=280<BR>\n" );
document.write( "-4x=-120<BR>\n" );
document.write( "x=30 lbs. (amount of $4 coffee)<BR>\n" );
document.write( "50-x=20 lbs. (amount of $8 coffee)<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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