document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=362589>Question 362589</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me here: \"The perimeter of a rectangular sign is 58cm and its area is 204cm^2. Find the length and width of the sign.\" If you may, please provide a step by step process so i can learn how to do it, instead of just getting the answer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #258457 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=258457\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2L+2W=58 FOR THE PERIMETER.<BR>\n" );
document.write( "LW=204 FOR THE AREA.<BR>\n" );
document.write( "L=204/W NOW REPLACE L WITH (204/W) IN THE FIRST EQUATION & SOLVE FOR W.<BR>\n" );
document.write( "2(204/W)+2W=58<BR>\n" );
document.write( "408/W+2W=58<BR>\n" );
document.write( "(408+2W*W)/W=58<BR>\n" );
document.write( "(408+2W^2)/W=58 CROSS MULTIPLY.<BR>\n" );
document.write( "2W^2+408=58*W<BR>\n" );
document.write( "2W^2+408=58W<BR>\n" );
document.write( "2W^2-58W+408=0<BR>\n" );
document.write( "2(W^2-29W+204)=0<BR>\n" );
document.write( "(W-17)(W-12)=0<BR>\n" );
document.write( "W-17=0<BR>\n" );
document.write( "W=17 ANS.<BR>\n" );
document.write( "W-12=0<BR>\n" );
document.write( "W=12 ANS.<BR>\n" );
document.write( "L=204/17=12 ANS.<BR>\n" );
document.write( "L=204/12=17 ANS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "12*17=204<BR>\n" );
document.write( "204=204 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );