document.write( "Question 362593: The sum of two numbers is 25. One number is 7 less than 3 times the other number.
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document.write( "x=larger number
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document.write( "y=lesser number\r
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document.write( "This is what I have so far. What do I do next?
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document.write( "x=9
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document.write( "x+y=120 \n" );
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Algebra.Com's Answer #258455 by checkley77(12844) ![]() You can put this solution on YOUR website! x=9 \n" ); document.write( "x+y=120 \n" ); document.write( "QUESTION? \n" ); document.write( "WHERE DID YOU GET X=9 & X+Y=120??????? \n" ); document.write( "------------------------------------- \n" ); document.write( "X+Y=25 OR X=25-Y \n" ); document.write( "X=3Y+7 \n" ); document.write( "25-Y=3Y+7 \n" ); document.write( "-Y-3Y=7-25 \n" ); document.write( "-4Y=-18 \n" ); document.write( "Y=-18/-4 \n" ); document.write( "Y=4.5 ANS. FOR THE SMALLER NUMBER. \n" ); document.write( "X=25-4.5 \n" ); document.write( "X=20.5 ANS. FOR THE LARGER NUMBER. \n" ); document.write( "PROOF: \n" ); document.write( "20.5=3*4.5+7 \n" ); document.write( "20.5=13.5+7 \n" ); document.write( "20.5=20.5 \n" ); document.write( " |