document.write( "Question 362599: A horse and two cows together cost $680. Find the cost of a cow and a horse, if a horse cost $80 more than a cow. \n" ); document.write( "
Algebra.Com's Answer #258450 by checkley77(12844) ![]() You can put this solution on YOUR website! H=C+80 \n" ); document.write( "H+2C=680 \n" ); document.write( "(C+80)+2C=680 \n" ); document.write( "C+80+2C=680 \n" ); document.write( "3C=680-80 \n" ); document.write( "3C=600 \n" ); document.write( "C=600/3 \n" ); document.write( "C=$200 COST OF ONE COW. \n" ); document.write( "H=2*200+80=400+80=$480 COST OF ONE HORSE. \n" ); document.write( "PROOF: \n" ); document.write( "480+200=680 \n" ); document.write( "680=680 \n" ); document.write( " \n" ); document.write( " |