document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=362533>Question 362533</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together to mix the 20 drinks? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #258427 by </B><A HREF=/tutors/aboutme.mpl?userid=HasanSahin><B>HasanSahin(52)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=HasanSahin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=HasanSahin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=258427\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First we have to compute how many drinks they can mix in a certain time..<BR>\n" );
document.write( "Steven can mix 4 drinks/min,Sue can mix 2 drinks/min, and Jack can mix (4/3)drinks/min \r<BR>\n" );
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document.write( "After then we will compute how much time it will take for 20 drinks such that;\r<BR>\n" );
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document.write( "[4dr/min + 2dr/min + (4/3)dr/min]*t = 20 dr<BR>\n" );
document.write( "[(22/3)dr/min]*t = 20 dr\r<BR>\n" );
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document.write( "So that t=30/11 min\r<BR>\n" );
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document.write( "RF.\r<BR>\n" );
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