document.write( "Question 362544: Solve the equation. Be sure to check your proposed solution by substituting for the variable in the original equation. \r
\n" );
document.write( "\n" );
document.write( "12(z+3)-4(z-1)=3(z-2)+4(z-1)\r
\n" );
document.write( "\n" );
document.write( "A. the solution set is { }
\n" );
document.write( "B. The solution set is all real numbers
\n" );
document.write( "C. The solution is an empty set \n" );
document.write( "
Algebra.Com's Answer #258390 by ghali0079(12)![]() ![]() ![]() You can put this solution on YOUR website! 12z+36 -4z+4 = 3z-6 +4z-4 \r \n" ); document.write( "\n" ); document.write( "now put all the Z's together on left and the rest on the right:\r \n" ); document.write( "\n" ); document.write( "12z -4z -3z-4z = -6-4-36-4\r \n" ); document.write( "\n" ); document.write( "1z = -50 \r \n" ); document.write( "\n" ); document.write( "z = -50. \n" ); document.write( " |