document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=362495>Question 362495</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Betty has 10 more dimes than quarters. If she has $3.45, how many coins does she have?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #258366 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=258366\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Betty has 10 more dimes than quarters. If she has $3.45, how many coins does she have? \r<BR>\n" );
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document.write( "d = q + 10<BR>\n" );
document.write( "10d + 25q = 345 cents<BR>\n" );
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document.write( "Substitute for \"d\" and solve for \"q\";<BR>\n" );
document.write( "10(q+10) + 25q = 345<BR>\n" );
document.write( "35q + 100 = 345<BR>\n" );
document.write( "35q = 245<BR>\n" );
document.write( "q = 7 (# of quarters)<BR>\n" );
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document.write( "Since d = q+10, d = 17 (# of dimes)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.  </SPAN>\n" );
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