document.write( "Question 362482: Can you please help me with this problem:Olimpiada Ivanova, a world-record holding race-walker, is on one end of a 6 mile track. John Doe, an average walker, is on the other end of the track. The two start walking towards each other and meet in 1/2 hour. If Olimpiada's average speed exceeds John's by 6 mph, find the speed of both walkers. Useing the 5-step method. Thankyou \n" ); document.write( "
Algebra.Com's Answer #258357 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Can you please help me with this problem:Olimpiada Ivanova, a world-record holding race-walker, is on one end of a 6 mile track. John Doe, an average walker, is on the other end of the track. The two start walking towards each other and meet in 1/2 hour. If Olimpiada's average speed exceeds John's by 6 mph, find the speed of both walkers. Useing the 5-step method. Thankyou \n" ); document.write( ".. \n" ); document.write( "john Doe speed = x mph \n" ); document.write( "Ivanova speed = x+6 mph.. \n" ); document.write( "they are walking towards each other so effective speed = x+x+6 \n" ); document.write( "=2x+6 mph. \n" ); document.write( ".. \n" ); document.write( "distance = 6 miles \n" ); document.write( "time = 1/2 hour \n" ); document.write( "speed = 2x+6 mph \n" ); document.write( "... \n" ); document.write( "6/(2x+6) =1/2 \n" ); document.write( "2x+6=2*6 \n" ); document.write( "2x+6 12 \n" ); document.write( "2x= 12-6 \n" ); document.write( "2x= 6 \n" ); document.write( "x= 3 mph speed of john \n" ); document.write( "Ivanova's speed = x+6 = 3+6 =9 mph \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |