document.write( "Question 362466: find the n needed to obtain a p-hat between (p-0.01, p+0.01) with 95% probability \n" ); document.write( "
Algebra.Com's Answer #258347 by stanbon(75887) ![]() You can put this solution on YOUR website! find the n needed to obtain a p-hat between \n" ); document.write( "(p-0.01, p+0.01) with 95% probability. \n" ); document.write( "------------ \n" ); document.write( "n = [z/E]^2*pq \n" ); document.write( "----- \n" ); document.write( "n = [1.96/0.01]^2*(1/2)(1/2) \n" ); document.write( "---- \n" ); document.write( "n = 9604 \n" ); document.write( "============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============== \n" ); document.write( " \n" ); document.write( " |