document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=362308>Question 362308</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the formula for a rectangle with a perimeter of 54\"? its width is 1/2 the legnth.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #258345 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=258345\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> W=L/2<BR>\n" );
document.write( "2L+2W=54<BR>\n" );
document.write( "2L+2(L/2)=54<BR>\n" );
document.write( "2L+L=54<BR>\n" );
document.write( "3L=54<BR>\n" );
document.write( "L=54/3<BR>\n" );
document.write( "L=18 ANS. FOR THE LENGTH.<BR>\n" );
document.write( "W=18/2=9 ANS. FOR THE LENGTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "2*9+2*18=54<BR>\n" );
document.write( "18+36=54<BR>\n" );
document.write( "54=54\r<BR>\n" );
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