document.write( "Question 40408: Kareem purchased a leather jacket for $800 with his new credit card. He budgeted $50 a month to pay toward the debt. When he read the fine print on the credit card statement, he saw that for each month he owed a balance, a finance charge of $17.50 would be added. How many months will it take Kareem to pay off the leather jacket?
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\n" ); document.write( "One machine in a print shop can produce a certain # of pages twice as fast as another machine. Operating together these machines can produce this number of pages in 8 minutes. How long would it take the slower machine working alone to produce this number of pages?
\n" ); document.write( "______minutes.
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Algebra.Com's Answer #25830 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Kareem purchased a leather jacket for $800 with his new credit card. He budgeted $50 a month to pay toward the debt. When he read the fine print on the credit card statement, he saw that for each month he owed a balance, a finance charge of $17.50 would be added. How many months will it take Kareem to pay off the leather jacket? \r
\n" ); document.write( "\n" ); document.write( "Let number of months needed to pay off the jacket be \"x\".
\n" ); document.write( "PAYING Data:
\n" ); document.write( " $50 per month for x months = 50x Dollars\r
\n" ); document.write( "\n" ); document.write( "OWING Data:
\n" ); document.write( "$800 + $17.5x \r
\n" ); document.write( "\n" ); document.write( "EQUATION:
\n" ); document.write( "50x=800+17.5x
\n" ); document.write( "32.5x=800
\n" ); document.write( "x=24.615....
\n" ); document.write( "Number of months will be 1 more than 24 or 25 months.
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\n" ); document.write( "\n" ); document.write( "One machine in a print shop can produce a certain # of pages twice as fast as another machine. Operating together these machines can produce this number of pages in 8 minutes. How long would it take the slower machine working alone to produce this number of pages?
\n" ); document.write( "______minutes.\r
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\n" ); document.write( "\n" ); document.write( "SLOWER MACHINE DATA:
\n" ); document.write( " Number of minutes for job= x; Rate of production = 1/x job/min
\n" ); document.write( "FASTER MACHINE DATA:
\n" ); document.write( " Number of minutes for job= 2x; Rate of production = 1/2x job/min
\n" ); document.write( "TOGETHER DATA:
\n" ); document.write( " Number of minutes fo job= 8; Rate of production = 1/8 job/min\r
\n" ); document.write( "\n" ); document.write( "EQUATION:
\n" ); document.write( " slower rate + raster rate = together rate
\n" ); document.write( "1/x + 1/2x = 1/8
\n" ); document.write( "Multiply through by 8x to get:
\n" ); document.write( "8+4=x
\n" ); document.write( "x=12 minutes (time for slower machine to do the job)
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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