document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=362311>Question 362311</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 2 centimeters less than 3 times its width. its area is 21 square centimeters find the dimensions of the rectangle   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #258291 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=258291\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 2 centimeters less than 3 times its width. its area is 21 square centimeters find the dimensions of the rectangle  <BR>\n" );
document.write( "..<BR>\n" );
document.write( "width =w<BR>\n" );
document.write( "length = 3w-2<BR>\n" );
document.write( "...<BR>\n" );
document.write( "L*W= Area<BR>\n" );
document.write( "w(3w-2)=21<BR>\n" );
document.write( "3w^2-2w=21<BR>\n" );
document.write( "3w^2-2w-21=0<BR>\n" );
document.write( "3w^2-9w+7w-21=0<BR>\n" );
document.write( "3w(w-3)+7(w-3)=0<BR>\n" );
document.write( "(w-3)(3w+7)=0<BR>\n" );
document.write( "..<BR>\n" );
document.write( "w=3 cm the width<BR>\n" );
document.write( "length = 3w-2<BR>\n" );
document.write( "Length =7 cm<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );