document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=362364>Question 362364</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hannah and Freancine have $120.00. Hannah and Peter have $230.00. Peter has 6 times as much money as Freancine. How much money does Hannah have? (real-world problems: Multiplication and Division) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #258265 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=258265\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> h +f = 120<BR>\n" );
document.write( "h + p = 230<BR>\n" );
document.write( "p = 6f<BR>\n" );
document.write( "Substitute the 3rd equation into the 2nd equation:  h + 6f = 230.  Then from this, h = 230-6f.  Put this into the 1st equation:  230-6f + f = 120, or<BR>\n" );
document.write( "-5f = -110, or f = 22.  This means h = 120-f = 120-22  = 98.  Hannah has $98.<BR>\n" );
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