document.write( "Question 362207: Please solve:
\n" ); document.write( " $\"+log%28+x%5E2%2C+9+%29+-+log%28+x%2C+36+%29+=+1+\"$ \n" ); document.write( "

Algebra.Com's Answer #258190 by HasanSahin(52) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"+log%28+x%5E2%2C+9+%29+-+log%28+x%2C+36+%29+=+1+\"$ \r
\n" ); document.write( "\n" ); document.write( "See the rule : $\"+log%28+a%5En%2C+b%5Em+%29++\"$ = $\"+%28m%2Fn%29+%2A+log%28a%2Cb%29+\"$ \r
\n" ); document.write( "\n" ); document.write( "In your question, $\"+log%28+x%5E2%2C+3%5E2+%29++\"$ = $\"+%282%2F2%29%2A+log%28x%2C3%29+\"$ \r
\n" ); document.write( "\n" ); document.write( "The problem becomes;\r
\n" ); document.write( "\n" ); document.write( " $\"+log%28x%2C3%29+-+log%28+x%2C+36+%29+=+1+\"$ \r
\n" ); document.write( "\n" ); document.write( "See rule 2 : $\"+log%28+a%2C%28x%2Fy%29+%29++\"$ = $\"+log%28+a%2Cx+%29++\"$ - $\"+log%28a%2Cy%29+\"$ \r
\n" ); document.write( "\n" ); document.write( "So that >> $\"+log%28x%2C3%29+-+log%28+x%2C+36+%29+=+1+\"$ = $\"+log%28x%2C3%2F36%29+\"$ \r
\n" ); document.write( "\n" ); document.write( "Therefore >> $\"+log%28x%2C1%2F12%29+=+1+\"$ \r
\n" ); document.write( "\n" ); document.write( "See rule 3 : $\"+log%28a%2Ca%29+=+1+\"$ \r
\n" ); document.write( "\n" ); document.write( "Therefore >> x = 1/12\r
\n" ); document.write( "\n" ); document.write( "RF.
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