document.write( "Question 362218: Please solve:
\n" ); document.write( " $\"+%28x-1%29%5E+%281%2F3%29+=+sqrt%28+x+%29+\"$ \n" ); document.write( "

Algebra.Com's Answer #258135 by HasanSahin(52) $\"\"$ $\"About$

You can put this solution on YOUR website!
The point is that you have to get out of square root and fraction in both sides..\r
\n" ); document.write( "\n" ); document.write( "If you take 6th degree of square of both sides you'll solve this..Observe >>\r
\n" ); document.write( "\n" ); document.write( " $\"+%28%28x-1%29%5E+%281%2F3%29%29%5E6+=+%28sqrt%28+x+%29%29%5E6+\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"+%28x-1%29%5E2+=+x%5E3+\"$ as (1/3)*6 = 2(left side) and 6/2 = 3 (right side)\r
\n" ); document.write( "\n" ); document.write( "After then >>\r
\n" ); document.write( "\n" ); document.write( " $\"+x%5E2+-+2x+%2B+1+=+x%5E3+\"$ so that $\"+x%5E3+-+x%5E2+%2B+2x+-+1+=+0+\"$ \r
\n" ); document.write( "\n" ); document.write( "You can not solve this immediately as it's not a regular cubic equation. You have to find roots.Check from any search engine to find roots of cubic equation.\r
\n" ); document.write( "\n" ); document.write( "RF. \n" ); document.write( "

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