document.write( "Question 362124: Please could someone kindly help me???\r
\n" ); document.write( "\n" ); document.write( "This is my question:\r
\n" ); document.write( "\n" ); document.write( "The perimeter of a rectangle is 140in. The length is 28in. greater than the width. Find the width of the rectangle.\r
\n" ); document.write( "\n" ); document.write( "This is how I'm doing it could you tell me if its right???\r
\n" ); document.write( "\n" ); document.write( "2(x+28)=140
\n" ); document.write( "2x+56=140
\n" ); document.write( "2x=140-56
\n" ); document.write( "2x=84
\n" ); document.write( "2 2
\n" ); document.write( "x=42
\n" ); document.write( "42 Divide 2
\n" ); document.write( "=21 width\r
\n" ); document.write( "\n" ); document.write( "Please help:)
\n" ); document.write( "Thank you
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #258121 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
L=W+28
\n" ); document.write( "2L+2W=140
\n" ); document.write( "2(W+28)+2W=140
\n" ); document.write( "2W+56+2W=140
\n" ); document.write( "4W=140-56
\n" ); document.write( "4W=84
\n" ); document.write( "W=84/4
\n" ); document.write( "W=21 ANS. FOR THE WIDTH.
\n" ); document.write( "L=21+28=49 ANS. FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*49+2*21=140
\n" ); document.write( "98+42=140
\n" ); document.write( "140=140
\n" ); document.write( "
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