document.write( "Question 362129: Solve.
\n" ); document.write( "the length of a rectangle field is 6m less than twice the width. the perimeter is 312m. find the length of the feild.
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Algebra.Com's Answer #258115 by checkley77(12844)\"\" \"About 
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L=2W-6
\n" ); document.write( "2L+2W=312
\n" ); document.write( "2(2W-6)+2W=312
\n" ); document.write( "4W-12+2W=312
\n" ); document.write( "6W=312+12
\n" ); document.write( "6W=324
\n" ); document.write( "W=324/6
\n" ); document.write( "W=54 m. ans. for the width.
\n" ); document.write( "L=2*54-6=108-6=102 m. ans. for the length.
\n" ); document.write( "Proof:
\n" ); document.write( "2*102+2*54=312
\n" ); document.write( "204+108=312
\n" ); document.write( "312=312
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