document.write( "Question 362137: How many ounces of 35% solution of sulfuric acid(and distilled water) must be mixed with 12 ounces of a 20% solution to get a 30% solution of sulfuric acid? \n" ); document.write( "
Algebra.Com's Answer #258109 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .35x+.20*20=.30(20+x) \n" ); document.write( ".35x+4=6+.30x \n" ); document.write( ".35x-.30x=6-4 \n" ); document.write( ".05x=2 \n" ); document.write( "x=2/.05 \n" ); document.write( "x=40 ounces of 35% solution is used. \n" ); document.write( "Proof: \n" ); document.write( ".35*40+.20*20=.30(20+40) \n" ); document.write( "14+4=.30*60 \n" ); document.write( "18=18 \n" ); document.write( " \n" ); document.write( " |