document.write( "Question 362137: How many ounces of 35% solution of sulfuric acid(and distilled water) must be mixed with 12 ounces of a 20% solution to get a 30% solution of sulfuric acid? \n" ); document.write( "
Algebra.Com's Answer #258109 by checkley77(12844)\"\" \"About 
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.35x+.20*20=.30(20+x)
\n" ); document.write( ".35x+4=6+.30x
\n" ); document.write( ".35x-.30x=6-4
\n" ); document.write( ".05x=2
\n" ); document.write( "x=2/.05
\n" ); document.write( "x=40 ounces of 35% solution is used.
\n" ); document.write( "Proof:
\n" ); document.write( ".35*40+.20*20=.30(20+40)
\n" ); document.write( "14+4=.30*60
\n" ); document.write( "18=18
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