document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=362050>Question 362050</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My cars cooling system holds 4.5 litres.  I put 1.5 litres of pure antifreeze and 3 litres of water in it. (33.33% antifereeze?)  I have since drained 1 litre of this mixture and topped up with 1 litre of pure antifreeze.  Could you please advise me how much of this new mixture I need to drain in order to achieve a 50/50 mix of antifreeze/water by topping up with pure antifreeze?\r<BR>\n" );
document.write( "\n" );
document.write( "Many many thanks in advance, Wayne </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #258104 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=258104\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> AF starting amount ___ 1.5 or 3/2 L (or 9/6)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "AF amount drained ___ (1.5)(1 / 4.5) = 1/3 L or 2/6\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "AF current amount ___ (9/6) - (2/6) + (6/6) = 13/6\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "current concentration ___ (13/6) / (9/2) = 13/27\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "[(9/2) - x](13/27) + (x)(100%) = (9/2)(50%)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "(13/6) - (13x/27) + x = 9/4\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "multiplying by 108 (LCD) ___ 236 - 52x + 108x = 243 ___ 56x = 7\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x = 1/8 L\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );