document.write( "Question 362089: The area of a rectangle is 168 square ft. Determine the length, width, and diagonal of a rectangle if the length is 3 feet greater than 3 times the width. \n" ); document.write( "

Algebra.Com's Answer #258087 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi, 
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document.write( "Let x represent the width.  then the length is (3x+3)
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document.write( "Area is l*w
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document.write( "(3x+3)*x == 168ft^2
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document.write( "3x^2 + 3x = 168ft2
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document.write( "3x^ + 3x - 168 = 0
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document.write( "x^ + x - 56 =0
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document.write( "factoring
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document.write( "(x - 8)(x+7)= 0
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document.write( "x = 8  the width is 8ft
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document.write( "x = -7 cannot use
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document.write( "width is 8 and the length is 27 (3*8 + 3)
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document.write( "finding d the diagonal implementing the Pythagorean Therem
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document.write( "8^2+ 27^2 = d^2
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document.write( "d = 28.160 ft \n" );
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