document.write( "Question 362077: quantity of 40% acid solution and another quantity of 10% acid solution must be mixed to form 15L of solution that 20% acid. how much of each must be mixed? \n" ); document.write( "

Algebra.Com's Answer #258072 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi, 
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document.write( "Let x represent the amount of 40% solution 
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document.write( "then (15L -x) will be the amount of the 10% solution
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document.write( ".40x + .10(15L-x)= .20*15L
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document.write( "solving for x
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document.write( ".30x = .10*15L
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document.write( "x = 5L of the 40% solution and 10L of the 10% solution\r
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document.write( "checking our answer
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document.write( ".40*5 + .10 *10 =  2 + 1 = 3= .20*15 \n" );
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