document.write( "Question 362045: You leave your home going 40 mph and arrive at work 1 minute late.
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document.write( "the next day you leave your home going 45 mph and arrive 1 minute early.\r
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document.write( "Question: How far away is your work? \n" );
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Algebra.Com's Answer #258066 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! 40 mph = 2/3 mi/minute \n" ); document.write( "45 mph = 3/4 mi/minute \n" ); document.write( "The difference in time is 2 minutes. \n" ); document.write( "---------------- \n" ); document.write( "d/(3/4) = d/(2/3) - 2 \n" ); document.write( "4d/3 = 3d/2 - 2 = (3d-4)/2 \n" ); document.write( "8d = 3(3d-4) = 9d - 12 \n" ); document.write( "d = 12 miles \n" ); document.write( "------------- \n" ); document.write( "12 miles @ 40 mph --> 18 minutes \n" ); document.write( "12 miles @ 45 mph --> 16 minutes \n" ); document.write( " \n" ); document.write( " |