document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=362020>Question 362020</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Dmitri needs 5 liters of a 43% solution of sulfuric acid for a research project in molecular biology.  He has two supplies of sulfuric acid solution: one is an unlimited supplyo f the 40% solution and the other an unlimited supply of the 45% solution.  How many liters of each solution should Dmitri use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #258039 by </B><A HREF=/tutors/aboutme.mpl?userid=CharlesG2><B>CharlesG2(834)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CharlesG2><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=258039\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Dmitri needs 5 liters of a 43% solution of sulfuric acid for a research project in molecular biology.  He has two supplies of sulfuric acid solution: one is an unlimited supply of the 40% solution and the other an unlimited supply of the 45% solution.  How many liters of each solution should Dmitri use?\r<BR>\n" );
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document.write( "% A * amount A + %B * amount B = %C * amount C<BR>\n" );
document.write( "40% * A + 45% * B = 43% * 5 liters<BR>\n" );
document.write( "let B = 5 - A<BR>\n" );
document.write( "0.40 * A + 0.45 * (5 - A) = 0.43 * 5<BR>\n" );
document.write( "0.4A + 2.25 - 0.45A = 2.15<BR>\n" );
document.write( "-0.05A = -0.1<BR>\n" );
document.write( "A = 2 liters of the 40%<BR>\n" );
document.write( "B = 5 - A = 5 - 2 = 3 liters of the 45%<BR>\n" );
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