document.write( "Question 40405: Sliced turkey cost $3.20 per pound. Roast beef cost twice as much, & ground beef cost half as much as the turkey. Find the price of 7.5 pounds of ground beef.
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\n" ); document.write( "A coffee shop mixes Brazilian coffee worth $5 per kilogram with Turkish coffee worth $8 per kilogram. The mixture is to sell for $7 per kilogram. How much of the Brazilian coffee should be used to make 300kg of the mixture? ____________kilograms
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Algebra.Com's Answer #25801 by josmiceli(19441)\"\" \"About 
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Sliced turkey cost $3.20 per pound.
\n" ); document.write( "ground beef cost half as much as the turkey.
\n" ); document.write( "Find the price of 7.5 pounds of ground beef.
\n" ); document.write( "$3.20 per pound / 2 = $1.60 / pound
\n" ); document.write( "(1.60 / lb)*(7.5 lb) = $12
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\n" ); document.write( "Let x = kg of Brazilian coffee in mixture
\n" ); document.write( "Let y = kg of Turkish coffee in mixture
\n" ); document.write( "($5/kg)*(x kg) + ($8/kg)*(y kg) = ($7/ kg)*(300 kg)
\n" ); document.write( "x kg + y kg = 300 kg
\n" ); document.write( "leaving out the units,
\n" ); document.write( "5x + 8y = 2100
\n" ); document.write( " x + y = 300
\n" ); document.write( "multiply 2nd equation by 5 and subtract from 1st
\n" ); document.write( "5x + 8y = 2100
\n" ); document.write( "-5x -5y = -1500
\n" ); document.write( "3y = 600
\n" ); document.write( "y = 200
\n" ); document.write( "x = 300 - y
\n" ); document.write( "x = 100
\n" ); document.write( "So, 100 kg of the Brazilian coffee should be used
\n" ); document.write( "check:
\n" ); document.write( "5x + 8y = 2100
\n" ); document.write( "5*100 + 8*200 = 2100
\n" ); document.write( "500 + 1600 = 2100
\n" ); document.write( "2100 = 2100
\n" ); document.write( "x + y = 300
\n" ); document.write( "100 + 200 = 300
\n" ); document.write( "300 = 300
\n" ); document.write( "OK
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