document.write( "Question 40405: Sliced turkey cost $3.20 per pound. Roast beef cost twice as much, & ground beef cost half as much as the turkey. Find the price of 7.5 pounds of ground beef.
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document.write( "A coffee shop mixes Brazilian coffee worth $5 per kilogram with Turkish coffee worth $8 per kilogram. The mixture is to sell for $7 per kilogram. How much of the Brazilian coffee should be used to make 300kg of the mixture? ____________kilograms
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Algebra.Com's Answer #25801 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! Sliced turkey cost $3.20 per pound. \n" ); document.write( "ground beef cost half as much as the turkey. \n" ); document.write( "Find the price of 7.5 pounds of ground beef. \n" ); document.write( "$3.20 per pound / 2 = $1.60 / pound \n" ); document.write( "(1.60 / lb)*(7.5 lb) = $12 \n" ); document.write( "-------------------------- \n" ); document.write( "Let x = kg of Brazilian coffee in mixture \n" ); document.write( "Let y = kg of Turkish coffee in mixture \n" ); document.write( "($5/kg)*(x kg) + ($8/kg)*(y kg) = ($7/ kg)*(300 kg) \n" ); document.write( "x kg + y kg = 300 kg \n" ); document.write( "leaving out the units, \n" ); document.write( "5x + 8y = 2100 \n" ); document.write( " x + y = 300 \n" ); document.write( "multiply 2nd equation by 5 and subtract from 1st \n" ); document.write( "5x + 8y = 2100 \n" ); document.write( "-5x -5y = -1500 \n" ); document.write( "3y = 600 \n" ); document.write( "y = 200 \n" ); document.write( "x = 300 - y \n" ); document.write( "x = 100 \n" ); document.write( "So, 100 kg of the Brazilian coffee should be used \n" ); document.write( "check: \n" ); document.write( "5x + 8y = 2100 \n" ); document.write( "5*100 + 8*200 = 2100 \n" ); document.write( "500 + 1600 = 2100 \n" ); document.write( "2100 = 2100 \n" ); document.write( "x + y = 300 \n" ); document.write( "100 + 200 = 300 \n" ); document.write( "300 = 300 \n" ); document.write( "OK \n" ); document.write( " |