document.write( "Question 361965: Two runners leave from the same location traveling in opposite directions. The first runner is running at 8 mph and the second is running at 10 mph. How long have they been running when they are 36 miles apart?
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Algebra.Com's Answer #257999 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "Note: d = r*t or t= d/r
\n" ); document.write( "Let x represent the distance the first runner travels, (36-x) will be the other's
\n" ); document.write( "each will have traveled the same amount of time
\n" ); document.write( "\"%28x%2F8%29+=+%28%2836-x%29%2F10%29\"
\n" ); document.write( "cross multiply to slove for x
\n" ); document.write( "10x = 8*36 - 8x
\n" ); document.write( "18x = 8*36
\n" ); document.write( "x = 16mi
\n" ); document.write( "t = d/r
\n" ); document.write( "t = 16/8 = 2 hrs
\n" ); document.write( "checking our answer
\n" ); document.write( "2hr*8mph + 2hr*10mph = 36mi apart \n" ); document.write( "
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