document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=40433>Question 40433</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the direction is to simplify the expressions using the inverse relationship between logarithms and exponents\r<BR>\n" );
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document.write( "ll^log11x\r<BR>\n" );
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document.write( "ln^ex\r<BR>\n" );
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document.write( "e^lnx<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #25797 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=25797\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ll^log11x = x<BR>\n" );
document.write( "ln^ex = x<BR>\n" );
document.write( "e^lnx =x\r<BR>\n" );
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document.write( "You will see the meaning of these answers if you understand<BR>\n" );
document.write( "that \"log\" or \"ln\" means exponent or power.\r<BR>\n" );
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document.write( "In the 1st problem you are raising 11 to the power of 11 that<BR>\n" );
document.write( "gives you x.  You therefore get x as the answer.\r<BR>\n" );
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document.write( "The same reasoning results in each of those answers be \"x\".<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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