document.write( "Question 361900: The area of a garden is 1920 square feet, and the length of its diagonal is 68 feet. Find the dimensions of the garden. \n" ); document.write( "

Algebra.Com's Answer #257954 by mananth(16946) $\"\"$ $\"About$

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The area of a garden is 1920 square feet, and the length of its diagonal is 68 feet. Find the dimensions of the garden.
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\n" ); document.write( "area = L*W=1920
\n" ); document.write( "diagonal = 68
\n" ); document.write( "..
\n" ); document.write( "L=1920/W
\n" ); document.write( "..
\n" ); document.write( "use pythagoras theorem
\n" ); document.write( "(1920/w)^2+w^2=68^2
\n" ); document.write( "3686400 +w^4=4625w^2
\n" ); document.write( "w^4-4625^2+3686400=0
\n" ); document.write( "use quadratic formula
\n" ); document.write( "discriminant = 6605025
\n" ); document.write( "x1=(4625+sqrt(6645025))/2
\n" ); document.write( "x1=w^2 (taking only positve values of w^2)& rounding off The decimals
\n" ); document.write( "x1= 3601.39
\n" ); document.write( "Take square root we w=60
\n" ); document.write( "length = 1920/60
\n" ); document.write( "Length = 30
\n" ); document.write( "The dimensions are 60 by 32
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( "60*32= 1920 \n" ); document.write( "

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