document.write( "Question 361902: Find the equation of the line that is parallel to the line formed by the equation 3x + 2y = -20 and passes through the point (-24, 12). \n" ); document.write( "

Algebra.Com's Answer #257948 by mananth(16946) $\"\"$ $\"About$

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Find the equation of the line that is parallel to the line formed by the equation 3x + 2y = -20 and passes through the point (-24, 12).
\n" ); document.write( "//
\n" ); document.write( "3x + 2y = -20
\n" ); document.write( "add -3x
\n" ); document.write( "2y=-3x-20
\n" ); document.write( "/2
\n" ); document.write( "y=-3x/2-10
\n" ); document.write( "..
\n" ); document.write( "compare this equation with y=mx +b
\n" ); document.write( "m= slope = -3/2
\n" ); document.write( "..
\n" ); document.write( "Parallel line will also have same slope = -3/2
\n" ); document.write( "...
\n" ); document.write( "to find b
\n" ); document.write( "plug value of point (-24,12) & m
\n" ); document.write( "12=(-3/2)*-24 +b\r
\n" ); document.write( "\n" ); document.write( "12=36+b
\n" ); document.write( "add-36
\n" ); document.write( "12-36=b
\n" ); document.write( "b=-14
\n" ); document.write( "...
\n" ); document.write( "the required equation is y = (-3x/2)-14
\n" ); document.write( "..
\n" ); document.write( " $\"graph%28300%2C300%2C-5%2C5%2C-15%2C15%2C%28%28-3x%2F2%29-14%29%2C%28%28-3x%2F2%29-10%29%29\"$
\n" ); document.write( "..
\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( "

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