document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=361734>Question 361734</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An algebra teacher drove by a farmyard full of chickens and pigs. The teacher happened to notice that there were a total of 100 heads and 270 legs. How many chickens were there? how many pigs were there? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #257924 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=257924\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> c +p =100,<BR>\n" );
document.write( "2c + 4p = 270.  The top equation gives c = 100-p.  Substituting into the bottom equation, 2(100-p) + 4p = 270.<BR>\n" );
document.write( "200-2p+4p = 270,<BR>\n" );
document.write( "2p = 70,<BR>\n" );
document.write( "p = 35, so there are 35 pigs, and 100-35 = 65 chickens. </SPAN>\n" );
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