document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=361807>Question 361807</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You are planning to put a new digital flat TV on a wall that is 12 ft long and 9 ft<BR>\n" );
document.write( "high. The digital TV has a diagonal of 72 inches. The length of the TV is twice<BR>\n" );
document.write( "the width of the TV. How much of the wall will still need to be decorated<BR>\n" );
document.write( "around the TV? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #257897 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=257897\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area of wall = 9*12 = 108 ft^2<BR>\n" );
document.write( "...<BR>\n" );
document.write( "width of TV = x<BR>\n" );
document.write( "Length = 2x\r<BR>\n" );
document.write( "\n" );
document.write( "...<BR>\n" );
document.write( "diagonal of TV = 72 \"= 6 ft<BR>\n" );
document.write( "..<BR>\n" );
document.write( "x^2+(2x)^2=6^2<BR>\n" );
document.write( "x^2+4x^2=36<BR>\n" );
document.write( "5x^2=35<BR>\n" );
document.write( "x^2=36/5<BR>\n" );
document.write( "x = sqrt(36/5)<BR>\n" );
document.write( "width = 2.68 ft.<BR>\n" );
document.write( "length = 2.68*2=5.36 ft<BR>\n" );
document.write( "Area of TV = 2.68*5.36<BR>\n" );
document.write( "=14.36ft^2<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Area of Wall - Area of TV= 108-14.36 = 93.63 ft^2<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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