document.write( "Question 361795: Two planes leave Pittsburgh and Philadelphia at the same time, each going to the other city. One plane flies 25 miles per hour faster than the other. Find the air speed of each plane if the cities are 275 miles apart and the planes pass each other after 40 minutes of flying time. \n" ); document.write( "
Algebra.Com's Answer #257890 by mananth(16946) You can put this solution on YOUR website! Two planes leave Pittsburgh and Philadelphia at the same time, each going to the other city. One plane flies 25 miles per hour faster than the other. Find the air speed of each plane if the cities are 275 miles apart and the planes pass each other after 40 minutes of flying time. \n" ); document.write( "... \n" ); document.write( "the planes are flying towards each other \n" ); document.write( "one plane speed = xmph \n" ); document.write( "other plane speed = x+25 \n" ); document.write( ".. \n" ); document.write( "effective speed = x+25+x= 2x+25 mph \n" ); document.write( "... \n" ); document.write( "40 minutes = 2/3 hours \n" ); document.write( "time = distance / speed \n" ); document.write( "275/(2x+25)=2/3 \n" ); document.write( ".. \n" ); document.write( "3*275 = 2(2x+25) \n" ); document.write( "825=4x+50 \n" ); document.write( "825-50=4x \n" ); document.write( "775=4x \n" ); document.write( "x= 775/4 \n" ); document.write( "193.75 mph speed of one plane. \n" ); document.write( "193.75+25 =218.75mph = speed of other plane \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |